Question

The resistance of conductivity cell containing
0.00/ No kd solution at 298 ků 1500 ohm. What is
the cell constant ich the conductivity of 0.001 skel
Solection at 298k is 0.14 6x16 sunt?​

Answer 1

Answer:

Explanation:

Question 9:The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 500M. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3S cm−1.

Answer:Given that ,

Conductivity of the cell , κ = 0.146 × 10−3 S cm−1

Resistance of the cell , R = 1500 Ω

Formula of cell constant

Cell constant = κ × R

Plug the values we get

= 0.146 × 10−3 × 1500

= 0.219 cm−1