Question

The resistance of the bulb filament is 100: at a temperature of 100°c. if its temperature co-efficient of resistance be 0.005 per °c, its resistance will become 200: at a temperature

Answer 1

From the given data when applied to the formula R0=R(1+alpha∆t) we get

200 = 100[1 +(0.005 × ∆t)]
T− 100 = 200
T = 300° C



From the given data when applied to the formula R0=R(1+alpha∆t) we get

200 = 100[1 +(0.005 × ∆t)]
T− 100 = 200
T