Question

the resistance of the conducting wire x of length length 1 sim 1 metre is 5ohm calculate the resistance of wire made by the same material whose length is 4 times and area of cross section 5 times of the wire x​

Answer 1

Answer:answer is 6.25 ohm

Explanation:as R=pA/l

5=pA/1

pA=5

A=5/p

As given that area of cross section is 5times the 1st one therefore substitute value of A in this down equation

R=p×5×5/p/l

R=25/4

R=6.25 ohm

Answer 2

The resistance of the new wire is 4 ohms.

Resistance of wire is given as , $R=5\ \Omega$.

We know, Resistance of an material is :

$R=\dfrac{\rho L}{A}$ {   $\rho$ is specific resistance , L and A is length and area respectively }

Now,

$5=\dfrac{\rho L}{A}$

Let , resistance of new wire is $R'$.

Therefore , its resistance is given by :

$R'=\dfrac{\rho(4L)}{(5A)}=\dfrac{4}{5}\times \dfrac{\rho L }{A}=\dfrac{4\times 5}5=4\ \Omega\ .$    { Here $\rho$ remains same because material is same }

The resistance of the new wire is 4 ohms.

Hence, this is the required solution.

Learn More :

Resistance

https://brainly.com/question/9934524