Question

the resistance of the flament in a light bulb is 1000w .if the bulb is fed by a current from a source of potential difference 230V. how much current will flow through it?​

Answer 1

$\huge \text{ {\underline {ANSWER}}}$

Current flowing through it will be 0.23 A

$\huge \text{ {\underline {EXPLANATION}}}$

Given that,

Resistance = R = 1000Ω

Voltage or Potential difference = V = 230V

We know that, V = IR from Ohm's Law

where, V is the voltage or potential difference

            I is the current flowing

            R is the resistance

V = IR

or

I = V / R

Substituting the values we get,

I = 230 / 1000

I = 0.23 A

Answer 2

Answer:-

Given,

Resistance of the bulb (R) = 1000w ohms

Potential Difference (P.D) = 230 Volts

By definition if current we have ,

V = I R ( since ohms law)

=> I (current) = 230/1000

=> I = 0.23 A

Hence , the current flowing is 0.23 Amperes