Question

The resistance of the kettle element

Answer 1

$<marquee behavior =move bgcolor =skyblue><h1>BONJOUR ✿●‿●✿</h1></marquee >$

$<marquee behavior =move bgcolor =pink><h1>chanchal here ✿●‿●✿</h1></marquee >$

Kettles are among the simplest of household appliances. Lift the lid and peer inside and you'll see, at the very bottom of the water container, a coil of thick metal called the heating element.

When you plug the kettle into an electrical outlet, a large electric current flows into the heating element..

What are the properties of heating an element in a electric kettle?

How can I generate a home loan interest certificate? When I try to download from SBI online, a 'no certific...

I will answer by using a numerical analysis - First I will make a few assumptions about the conditions - ( remember that these numbers are approximations and actual values may be different but given the purpose of a kettle , i assume that these values are good enough )

Cold Water Temperature - 20 Deg C

Hot water Temperature - 100 Deg C

Weight of water in the kettle - 1000 ml ( 1 Liter ) = 1 kg

Specific heat of water - 4200 J /kg Deg C

Target time to heat the water - 300 Sec. ( 5 min )

AC mains supply Voltage - 230 V ( India , use 120 here for the USA )

Energy required to heat 1 liter of 20 deg. C water to 100 Deg. C =

(100–20) Deg. C * 1 kg * 4200 J /kg Deg. C = 336,000.00 J

Power output required from the heating element =

336000 / 500 = 672 W

Current required at 230 V to allow 672 Watts = 672 / 230 = 2.92 A

using V = IR ( R = V /I ) we get resistance = 78 Ohms ( approx. )