The resistance of the wire is R1. It is now stretched (keeping volume constant) without breaking so that its length becomes three times. Now the resistance becomes R2, then what is the value of R2 : R1 1) 1 : 3 2) 1 : 9 3) 9 : 1 4) 3 : 1
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Explanation:
The wire is stretched to double its length.
⟹l
′
=2l
The volume in the process remains the same.(Since mass is unchanged, and density remains same)
⟹l
′
A
′
=lA
⟹A
′
=A
′
=
2
A
l
If the initial resistance was R=
A
ρl
Hence R
′
=
A
′
ρl
′
=
A
4ρl
=4R
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