Question

The resistance of two conductors in series is 18omega and the resistance becomes 4omega when connected in parallel. Find the resistance of individual conductors
​

Answer 1

Answer:

R1=12 ohm

R2=6 ohm

Explanation:

in series.... Req = 12+6 = 18 ohm

in parallel....1/Req = 1/12+1/6

1/Req = 1/4

so, Req=4 ohm