the resistance offered by each bulb of the fairy light is 20 ohm .calculate
1) the total resistance due to 5 such bulbs of fairy light
2) if the potential difference of 50v is applied to its terminal,calculate the current flowing through it.
3) what would happen if one of the bulbs got fused or turned dead ? also state what need to be done in this situation
kaala:
hello
may i know , that in the 1st question bulbs are connected in series or in parallel
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is fairy light bulb
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Answers
Answered by
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The answer to your question is
( 1 ) Resistabce by bulb when taken in series is
R = 20 + 20 + 20 + 20 + 20
= 100 ohms
Resistance by bulb when taken in parallel is
1/R = 1/20 + 1/20 + 1/20 + 1/20 + 1/20
1/R = 5/20
R = 20/5
R = 4 ohms
( 2 ) When potential diff is 50V then I = ?
I = V/R
= 50/100
=0.5 A
I = V/R
=50/4
=12.5A
( 3 ) If the connection is fused then the bulb should be replaced .
Parallel connection should be preferred because it offers less resistance and if one bulb got fused the others will glow which will bot happen in series connection .
Hope it helps you .
Have a nice day .
( 1 ) Resistabce by bulb when taken in series is
R = 20 + 20 + 20 + 20 + 20
= 100 ohms
Resistance by bulb when taken in parallel is
1/R = 1/20 + 1/20 + 1/20 + 1/20 + 1/20
1/R = 5/20
R = 20/5
R = 4 ohms
( 2 ) When potential diff is 50V then I = ?
I = V/R
= 50/100
=0.5 A
I = V/R
=50/4
=12.5A
( 3 ) If the connection is fused then the bulb should be replaced .
Parallel connection should be preferred because it offers less resistance and if one bulb got fused the others will glow which will bot happen in series connection .
Hope it helps you .
Have a nice day .
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