The resistance per meter length of a wire is 100 ohm.If the resistivity of the material of the wire is 50*10^-8 ohm meter.Find the area of cross section of the wire.
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A=50*10^-8*10/100=5*10^-9m squarem
sorry my friend i just read wrong question you correct answer is 5into ten to power minus nine
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R ( resistance ) = 100 ohm
rho ( resistivity ) = 50*10^-8 ohm meter
L = 1m
we know that,
R =( rho * L ) / A
by substituting the above given values we get,
100 = {( 50*10^-8)*(1)} / A
A = {( 50*10^-8)*(1)} / 100
A = 5*10^-9 m^2
rho ( resistivity ) = 50*10^-8 ohm meter
L = 1m
we know that,
R =( rho * L ) / A
by substituting the above given values we get,
100 = {( 50*10^-8)*(1)} / A
A = {( 50*10^-8)*(1)} / 100
A = 5*10^-9 m^2
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