the resistance r=v/i where v=(100+5)or(100-5)v and i=(10+0.2) or (10-0.2). Find percentage error
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From the given data
V = 100. and ∆V = 5
I =10. and ∆I= 0.2
∆R/R% = ?
R = V/I
So ∆R/R = ∆V/V + ∆I/I
∆R/R = 5/100 + 0.2/10
=(5+2)/100
=7/100
∆R/R =0.07
∆R/R% = 0.07×100 = 7%
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