Question

the resistance r =v/i where v = (100+_5 )v and I = (10+_0.2) a.find percentage error in r

Answer 1

see the attachment.

Hope it helps.

Answer 2

Answer:

7 %

Explanation:

Given :

Potential difference V = ( 100 ± 5 ) V

Current I = ( 10 ± 0.2 ) A

From Ohm's law we have :

V = I R

R = V / I

Now :

% error in R = ( Δ V / V + Δ I / I ) × 100

% error in R = ( 5 / 100 + 0.2 / 10 ) × 100

% error in R = ( 7 / 100 ) × 100

% error in R = 7 %

Therefore , percentage error in resistance is 7 % .