Question

The resistance R = V/I where V = 100+-5volt and I = 10+-0.2A . Find percentage error in R.

Answer 1

Hey mate here is your answer :

Given that :
V = 100+-5V
I = 10+-0.2A

deltaR/R *100 = deltaV/V *100 + deltaI/I *100
= 5/100*100 + 0.2/10*100
= 5 + 2
= 7%

Thus the percentage error in Resistance is 7%

Answer 2

The resistance R = V/I where V = 100+-5volt and I = 10+-0.2A . Find percentage error in R.

Ans.  
The resistance R=V/I where v=(100+-5)a and I=(10+-0.2)a find the error in m

The resistance R=V/I where v=(100+-5)a and I=(10+-0.2)a find the error in measurement of resistance in measurement limits.

 v=(100+-5)a

I=(10+-0.2)a

R=V/I =100/10=10Ω

 ΔR/R=+_[ ΔV/V+  ΔI/I]

=+_[5/100+0.2/10]

=+_[7/100]

=+_0.07

 ΔR=R*0.07

=+_0.07*10

=0.7 ohms

Percentage error  ΔR/R*100=+_0.07*100=+_7 percent

SO MARK AS BRAINIEST PLEASE.