The resistance R = V/I ,where V = (40±0.4)V and I = (2±0.02) A. Find the error in R .
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Given :
Potential difference V = ( 100 ± 5 ) V
Current I = ( 10 ± 0.2 ) A
From Ohm's law we have :
V = I R
R = V / I
Now :
% error in R = ( Δ V / V + Δ I / I ) × 100
% error in R = ( 5 / 100 + 0.2 / 10 ) × 100
% error in R = ( 7 / 100 ) × 100
% error in R = 7 %
Therefore , percentage error in resistance is 7 % .
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