Question

the resistance to be used to convert a 50 omega resistance galvanometer of 10 ma in to 500 v range voltmeter​

Answer 1

The equt circuit diagram of 

voltmeter will be 

So, 

15=5×10−3(a+s)  [onm's law]

⇒3000=50+s

⇒2950 Ω=s

So, a 2950Ω resistor should 

be combined in series with

galvanometer to convert it in to voltmeter.

Answer 2

The resistance is 49950 Ω.

Given:

G = 50 Ω

Ig = 10 mA

V = 500 V

To Find:

The Resistance

Solution:

The resistance can be found by using the formula,

R = (V/Ig) - G

  = (500/10*10⁻³) -50

  = 5000 - 50

  = 49950 Ω

Hence, The resistance is 49950 Ω.

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