Question

The resistances of two resistors are in the ratio of 1:3. The resistance of their

parallel combination is 3Ω. What is the resistance of their series combination​

Answer 1

Answer:

Correct option is

A

(66.7 ± 1.8) Ω

Here, R

1

(100±3)Ω;R

2

=(200±4)Ω The equivalent resistance in parallel combination is

R

1

1

=

R

1

1

+

R

2

1

,

R

p

1

=

100

1

+

200

1

=

200

3

,R

p

=

3

200

=66.7Ω

The error in equivalent resistance is given by

R

p

2

ΔR

p

=

R

1

2

ΔR

1

+

R

2

2

ΔR

2

;ΔR

p

=ΔR

1

(

R

1

R

p

)

2

+ΔR

2

(

R

2

R

p

)

2

=3(

100

66.7

)

2

+

Answer 2

Explanation:

jejejdndndjdjdkdkdkdkdkd