Question

the resistense per meter length of a wire is 10 ohm. if the resistivity of the material of wire is 50^10 raised to - 8 find the area of cross section of the wire... Pls it's urgent​

Answer 1

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Answer 2

Given that, length of wire (l) = 1 m, Resistance (R) = 10Ω, resistivity (p) = 50 × 10^8-

We have to find the area of cross-section (A) of the wire.

Now,

R = p l/A

$\rule{100}1$

Here, The resistance of the conductor (wire) is directly proportional to the length of wire i.e. R ∝ l

Inversely proportional to the area of cross-section of wire i.e. R ∝ 1/A

R ∝ l/A

If we remove the sign of proportionality we use a constant i.e. p (rho).

So, R = p l/A

$\rule{100}1$

→ 10 = (50 × 10^8- × 1)/A

→ A = (50 × 10^8-)/10

→ A = 5 × 10^(8-) m^2