Question

the resister of 6 ohm,3ohm and 2ohm are connected in parallel it combination of resister is connected to another resister of 4ohm.the circuit consists of a cell of 1.5volt.
1.draw the circuit diagram.
2.total ohm of current flowing in each resister.​

Answer 1

Answer:

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the last part of the answer is

6 ohm → 1 / 4 ampere

3 ohm → 1 / 2 ampere

2 ohm → 3 / 4 ampere

4 ohm → 0.3 ampere

ae7ded519b9508e8756619e2cdedb844.pdf

Answer 2

Answer: I = 0.33 ampere

Explanation:

In parallel

1/R = 1/R1 + 1/R2 +1/R3

1/R = 1/6 + 1/3 + 1/2

1/R = 11/6 ohm

R= 6/11 = .0.545 ohm

The combination is connected to a 4 ohm resistor

Therefore, Req= 4 + 0.545

= 4.545ohm

V = 1.5 volt

V= IR

I = V/R = 1.5/4.545

= 0.33 ampere