The resistivity of a 0.2M solution of electrolyte is
5x10^- 3 ohm cm, calculate it molar conductivity
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Explanation:
The resistivity of a 0.2M solution of electrolyte is
5x10^- 3 ohm cm, calculate it molar conductivity
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Answered by
5
Answer:
Here the resistivity = 5×10^-3 ᘯcm
Therefore,
The conductivity of solution
k=1/p
=1/5×10^-3 ᘯcm
=1/5×10^3 ᘯ^-1 cm^-1
Molar conductivity
^M=1000×k/M
=10^3×1/5×10^3×1/0.8
=2.5×10^5 ᘯ^-1 cm^2 mol^-1.
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