Question

The resistivity of a 0.2M solution of electrotyte is 5×10-³omega cm,calcui it's molar conductivity

Answer 1

Answer:

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Explanation:

Molar conductivity= (1000×K)/M

where,

M=molarity

K= 1/resistivity

answer will be "10⁶" .

Answer 2

Given :

Resistivity of solution = 5 × 10‾³ Ω m

Molarity of solution = 0.2 M

To Find :

Molar conductivity of the solution.

Solution :

First of all we have to find conductivity of the solution.

Relation between resistivity and conductivity is given by :: $\kappa$ = 1 / ρ

• $\kappa$ denotes conductivity
• ρ denotes resistivity

$\sf:\implies\:\kappa=\dfrac{1}{\rho}$

$\sf:\implies\:\kappa=\dfrac{1}{5\times10^{-3}}$

$\sf:\implies\:\kappa=0.2\times 10^3$

$\bf:\implies\:\kappa=200\:S\:m^{-1}$

★ Molar conductivity $\bf{(\Lambda_m)}$ is the conductance of a solution containing 1 mole of electrolyte.

$\dag\:\underline{\boxed{\bf{\gray{\Lambda_m=\kappa\times\dfrac{1000}{Molarity}}}}}$

By substituting the given values;

$\sf:\implies\:\Lambda_m=200\times\dfrac{1000}{0.2}$

$\sf:\implies\:\Lambda_m=200\times 5000$

$:\implies\:\underline{\boxed{\bf{\orange{\Lambda_m=10^6\:S\:m^2\:mol^{-1}}}}}$