Question

The resistivity of a 0.8 M solution of electrolyte is 5x 10 ‐3Ωcm . calculate its molar conductivity .​

Answer 1

κ=1/5*10^-3    (κ=1/resistivity)

M=0.8 M

λm=κ/1000*M

λm=κ/0.8*1000

=1000/1000*0.8*5

=0.25 S m² mol⁻¹

hope this helps

Answer 2

Resistivity = 5/1000 ohm cm

Molarity = 0.8 M

Conductivity = 1/resistivity

= 100000/5

= 20000 s/m

Molar conductivity = k/C

= 20000/0.8×1000

= 25 s m^2 / mol

= 250000 s cm^2 / mol.