Question

The resistivity of a conductor in which a
current density 2.5 Am 2 is found to exit, when
an electric field 5x10- Vm-' is applied to it is

1) 1.0x10-2m
2) 2.0x10-12m
3) 0.5x10-2m
4) 12.5x10-82m​

Answer 1

Answer:

PLEASE GIVE ME A BRANLIAST ANSWER

from figure, length=l

so , i=(2.5Am

−2

)A

1

V=iR

E.l=2.5A

1

×

A

1

ρl

E=2.5(ρ)

ρ=

2.5

5×10

−8

=2×10

−8

Ωm

ρ=2×10

−8

Ωm

solution