Question

the resistivity of a metal wire is 10 into 10 to the power minus 8 ohm metre at 20 degree Celsius find the resistance of the same wire of 2 m length and 0.3 mm thickness with explanation

Answer 1

Answer: The resistance of the wire is 2.83 ohm.

Explanation:

Given that,

Resistivity of wire $\rho = 10\times10^{-8}\ \Omega m$

Length l = 2 m

Thickness t = 0.3 mm

We know that,

The resistance of the wire is

$R = \dfrac{\rho l}{A}$....(I)

Where, R = resistance

$\rho$ = resistivity of the wire

l = length of the wire

A = area of cross section

Put the all values in equation (I)

$R = \dfrac{10\times10^{-8}\times2}{3.14\times0.15\times0.15\times10^{-6}}$

$R = 2.83 \Omega$

Hence, The resistance of the wire is 2.83 ohm.

Answer 2

Answer:

so this is your answer bro