the resistivity of a wire is 10 ^ -5 ohm m. If the length of the wire is 10m and the area of cross section is 1mm^ 2 find the resistance of the wire .
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ind the resistance of a copper coil of total wire-length 10m and area of cross section 1.0mm^(2). What would be the resistance of a similar coil of aluminium? The resistivity of copper =1.7×10−8(Ω)m and that of aluminium2.6×10−8(Ω).
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Solution :
The resistance of the copper coil is
(ρ)(lA)=(1.7×10−8(Ω)m)×10m1.0×10−6m2=0.17(Ω).
Theresistanceofthesimilaraluminiumcoilwillbe((2.6xx10^(-8)(Omega)m)xx10m)/1.0xx10^(-6)m^(2))=0.26(Omega).
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Explanation:
R = p L/A
R = 10^-5 × 10 / 1 × 10^-3
R = 10^-4 / 10^-3
R = 10^-1 = 1/10 = 0.1 ohm
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