the resistivity of material is 10 ohm metre at 30 degree Celsius when the temperature drops to 28 degree Celsius then the resistivity drops by 2ohm meter . the temperature coefficient of resistivity of material is.
its correct ans is10per kelvin how?
Answers
Answer:
The resistance of a conductor at 20
∘
C is 3.15Ω and at 100
∘
C is 3.75Ω.
To find the temperature co-efficient of resistance of the conductor.
Solution:
Here R
20
=3.15,R
100
=3.75
We know that R
t
=R
0
(1+αt)
where R
0
= resistance at 0
∘
C
and R
t
= resistance at t
∘
C
α= temperature coefficient of resistance
Now,
R
20
=3.15=R
0
(1+20α)....(i)
R
100
=3.75=R
0
(1+100α)....(ii)
Dividing (i) and (ii), we get
R
0
(1+100α)
R
0
(1+20α)
=
3.75
3.15
⟹3.75(1+20α)=3.15(1+100α)
⟹3.75+75α=3.15+315α
⟹240α=0.6
⟹α=0.0025
∘
C
−1
From equation(i) ,
R
0
=
1+20α
3.15
⟹R
0
=
1+20(0.0025)
3.15
⟹R
0
=
1+0.05
3.15
⟹R
0
=3Ω
is the temperature co-efficient of resistance of the conductor.
Explanation:
Answer:
The resistivity of material is 10 ohm meter at 30°c when the temperature drops to 28°c then the resistance drops by 2 ohm metre the temperature coefficient of resistivity of materials is (correct answer is 10 per K)
Mark me as brainliest and subscribe to my channel UNIVERSAL IDOL PLEASE please