Physics, asked by Manav00003129843, 6 months ago

the resistivity of the material of a wire of length “l” and diameter “d” and resistance R is given by ρ=(πRd^2)/4l .The length of the wire l=100.00cm is using a meter scale with a least count of 1mm ,the diameter d=0.22cm is measured using an instrument having least count 0.01cm and resistance R= 5 ohm, is measured with an accuracy of 0.01 ohm .find % error Suggest a method to reduce %error.​

Answers

Answered by manojkumar14831733
0

Answer:

it's too lengthy bro in case you should increase some points

Similar questions