the resistiviy of micron wire 100micro ×ohm×cm . what length of wire of diameter 0.2mm is required to form a coil of resistance 20 ohm
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Given,
Resistivity = 100×10^-6 ohm/cm
Radius of wire = D/2 = 0.1mm = 10^-4m ;
Area of cross section = πr² = 3.14×10^-4×10^-4 = 3.14 × 10^-8 m².
Resistance = 20 ohm
Now,
R = ρl/A
l = RA/ρ
l = (20 × 3.14×10^-8)/100×10^-6
l = 0.00628m
l = 6.28 mm (Ans)
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