The resistor offered by each bulb of the fairy lights shown below is 20 ohm. If potential difference of 50V is applied to its terminal, calculate the current flowing through it.
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Answered by
1
V=IR
V=50V
R=20 ohm
I=V/R = 50/R
here you are not showing the diagram so I can't find the correct answer
but I can help you as
if they are in // combination then
1/Req = 1/R1 + 1/R2 + 1/R3......
if they are in series
Req = R1+R2+R3.....,.
if there are two series in // and their
and 3 and 5 are no. of rasistance in those series
then
R1=60
R2=100
Req = 600/16 = 75/2
I=50/75×2
= 4/3 amp
V=50V
R=20 ohm
I=V/R = 50/R
here you are not showing the diagram so I can't find the correct answer
but I can help you as
if they are in // combination then
1/Req = 1/R1 + 1/R2 + 1/R3......
if they are in series
Req = R1+R2+R3.....,.
if there are two series in // and their
and 3 and 5 are no. of rasistance in those series
then
R1=60
R2=100
Req = 600/16 = 75/2
I=50/75×2
= 4/3 amp
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0
Answer:your answer is given below
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