Question

the resistor r1 and r2 of 4ohm and 6 ohm are connected in parellal accros a battry the ratio of power dicipitated in them p1:p2 ​

Answer 1

Answer:

Explanation:

V = 6 , R1 = 4 , R2 = 6

Total Resistance

1/R = 1/4 + 1/6

1/R = 3/12 + 2/12

1/R = 5/12

R = 12/5 = 2.4 ohms

Power supplied by battery

P = V^2/R

P = (6*6)/2.4 = 36/2.4 = 15 Watt

Power dissipated in R1

P = V^2/R

P = (6*6)/4 = 36/4 = 9 Watt

[ P.d is same across every resistor in Parallel combination ]

Power disspitated in R2

P = 36/6 = 6 Watt