Science, asked by kumardharmedra578, 7 months ago

The resistors ,R1 =5 Ω,

R2=10 Ω, R3=30 Ω have been connected to a battery

of 12V.Calculate-

(a) the total circuit resistance,

(b) the current through each resistor and

(c) the total current in the circuit.​

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Answers

Answered by ishaphulwani
3

Answer:

I will think about it

Explanation:

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Answered by krishna02299
18

Answer:

a).

b). 5Ω = 2.4 A , 10Ω = 1.2 A , 20Ω = 0.6 A

c). 4.2 A

Explanation:

Given-

r1= 5Ω ,r2 = 10Ω , r3 = 20Ω

V = 12 ( battery

a). Total Resistance -

In Above Picture Resistance Connected In Parallel

So, Total Resistance is -

 \frac{1}{p}  \:  =  \:  \:  \frac{1}{5}   \:  +  \frac{1}{10}  \:  +  \frac{1}{20}

1/p = 1/3

So,

\bold{\boxed{P= 3}}

Resistance In Parallel= 3Ω

b). Current Through Each Resistor -

1. Current Through Resistor

R = 5Ω

V = 12v

= ?

Using Ohm's Law

i•e,

V= IR

So,

I = V/R

I = 12/5

= 2.4 A {Ampere)

2. Current Through 10Ω Resistor -

R = 10Ω

V = 12V

= ?

By Ohms Law

V = IR

So,

I = V/R

I = 12/10

= 1.2 A

3. Current Through 20Ω Resistor -

R = 20Ω

V =12 v

= ?

I = V/R

I = 12/20

= 0.6 A

So,

I¹= 2.4 A

I²= 1.2 A

I³= 0.6 A

c). Total Current -

We Have,

= 2.4 A , = 1.2 A , = 0.6 A

So Total Current Is

I = I¹ + I² + I³

I = 2.4 + 1.2 + 0.6

I = 4.2 A

❣️Hope This Help You ❣️

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