Question

The resistsnce of a wire is 10 ohm its length is increased by 10% by stretching . The new resistance will now be

Answer 1

Answer:

Explanation:

Handy trick

If the question doesn't gives clue about change in volume.

The new resistance =

{ 1+(x/100)}^2 of Initial resistance , where x= the increment percent.

Here in ur ques , x= 10% and R= 10 ohm

Therefore, the new resistance =

{1+(10/100)}^2 ×10

= { 110/100}^2 × 10= 12.1 ohm