Question

The resonant frequency of a circuit of negligible resistance containing one inductance of 50mH and a capacitance of 500pF connected in series is

Answer 1

Explanation:

$resonant \: frequency = 1 \div ( \sqrt{lc) } \\ resonant \: frequency = 1 \div ( \sqrt{50 \times {10}^{ - 3} \times 500 \times {10}^{ - 12} }) \\ resonant \: frequency = 1 \div (5 \times {10}^{ - 6} ) \\ resonant \: frequency = 2 \times {10}^{ - 7}$