Question

The respective volumes (in ml) of 0.2M-HCI and 0.6M-HCI to be mixed together for preparing
1000ml of 0.3M-HCI are
​

Answer 1

Answer:

750 ml of 0.2M HCl and 250ml of 0.6M HCL should be mixed for preparing 1000ml of 0.3M HCL

Explanation:

let, xm be the volume of 0.2M HCL and (1000 - x) ml be the volume of 0.6M HCL .

According to normality equation

volume of 0.2M HCL *  Strength of  1st HCl + volume of 0.6 M HCl 8* Strength of second HCl =  Mixed volume of HCl * Mixed strength of HCL

or, x * 0.2 + (1000 - x) * 0.6 = 0.3 * 1000

or, 0.2 x + 600 - 0.6 x = 300

or, 0.4 x = 300

or, x = 300/0.4

or, x = 750ml

and (1000-x)ml = (1000-750)ml = 250ml

Answer 2

Answer:750 ml of 0.2M HCl and 250ml of 0.6M HCL should be mixed for preparing 1000ml of 0.3M HCL

Explanation:

let, xm be the volume of 0.2M HCL and (1000 - x) ml be the volume of 0.6M HCL .

According to normality equation

volume of 0.2M HCL * Strength of 1st HCl + volume of 0.6 M HCl 8* Strength of second HCl = Mixed volume of HCl * Mixed strength of HCL

or, x * 0.2 + (1000 - x) * 0.6 = 0.3 * 1000

or, 0.2 x + 600 - 0.6 x = 300

or, 0.4 x = 300

or, x = 300/0.4

or, x = 750ml

and (1000-x)ml = (1000-750)ml = 250ml