Question

The resting heart rates of a group of healthy adult men were found to have a mean of 73.4 beats per minute, with a standarf deviation of 5.9 beats per minute. What percent of the men has a resting rate of:

a. greater that 80 beats per minute?
b. between 70 and 85 beats per minute?​

Answer 1

Answer:

Children (ages 6 - 15) 70 – 100 beats per minute

Adults (age 18 and over) 60 – 100 beats per minute

Step-by-step explanation:

Answer 2

Concept Introduction:-

It could take the shape of a word or a numerical representation of a quantity's arithmetic value.

Given Information:-

We have been given that the resting heart rates of a group of healthy adult men were found to have a mean of $73.4$ beats per minute, with a standard deviation of $5.9$ beats per minute.

To Find:-

We have to find that $a$. greater that $80$ beats per minute?

$b$. between $70$ and $85$ beats per minute?​

Solution:-

According to the problem

$a . p ( x > 80)$

=1-p(x \leqslant 80)\\

$80 \rightarrow(80-73.4) \div 5.9 \approx 1.12\\p(2 \leqslant 1.12)=0.8686\\\therefore P(x > 80)=1-0.8686\\=0.1314=13.14 \%$

$b \quad p(x\leq x \leqslant 85)\\\\70 \rightarrow(70-73.4) \div 5.9 \approx-0.58\\85 \rightarrow(85-73.4) \div 5.9 \approx 1.97\\p((2 \leqslant-0.58)=0.2810\\P(2\leqslant 1.97)=0.9756\\\therefore P(70 \leq x \leq 85)=0.9756-0.2810\\=0.6946\\=69.46 \%$

Final Answer:-

The correct answer are $a. 13.14 \%$ and $6.69 .46 \%$.

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