Question

The result of a dihybrid cross between two pure individuals tall and round seeded with dwarf and wrinkled seeded is recorded total number of seed obtained after Selfing of F1 = 1216
a.What would be the phenotype of F1 individuals?
b.How many seeds in F2 would be like parents of F1?
c.Which Mendelian principles helped you to conclude your answer?

Answer 1

Answer:

Correct option is A)

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

So, the correct option is ‘9:3:3:1’.