the resultant Ċ of A and B is perpendicular
to A. Also, AHC). The angle between Ā
and B is :
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Answer:
If C=A+b
and C is perpendicular to A
C . A =0
(A+b).A =0
if 0 is the angle between a and b
A2 + ABcos (0)= 0
0= cos -1 (-A\B)
using triangle law of cosines to present |C| in
terms of |A| and |B|
C2 =A2+B2 - 2 ABcos (0)
now we also know
|C| =| A|
A2= A2+B2 - 2Abcos (0)
0= cos -1 (B/2A).
please vote me
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