the resultant Ċ of A and B is perpendicular
to A. Also, IĀl =lCl. The angle between vector A
and vector B .
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Answer:
Let θ be the angle between vectors A and B
and ϕ be the angle between resultant C and vector A
ϕ=2π (since, C is perpendicular to A)
We know that,
ϕ=tan−1(A+BcosθBsinθ)......(1)
Magnitude of C=A2+B2+2ABcosθ
By squaring both sides:
C2=A2+B2+2ABcosθ
Since, A=C
A2=A2+B2+2ABcosθ
By this equation we get
A=2cosθ−B. ....(2)
Putting equation (2) in (1)
ϕ=tan−1⎝⎜⎜⎛2cosθ−B+Bcosθ
Explanation:
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