Question

The resultant capacitance of four plates, each is having an area A, arranged as shown above,
will be (plate separation is d)​

Answer 1

Answer:

2E°A/d

Both Capicitor are in parallel

C+ C = 2C

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Answer 2

The equivalent capacitance between A and B is $\dfrac{2\epsilon_{0}A}{d}$

Explanation:

Given that,

Area = A

Distance = d

The given circuit is equivalent to a parallel combination two identical capacitors

After simplify the circuit,

Both capacitor in parallel

We need to calculate the equivalent capacitance between A and B

Using formula of capacitor

$C'=C_{1}+C_{2}$

Put the value into the formula

$C'=\dfrac{\epsilon_{0}A}{d}+\dfrac{\epsilon_{0}A}{d}$

$C'=\dfrac{2\epsilon_{0}A}{d}$

Hence, The equivalent capacitance between A and B is $\dfrac{2\epsilon_{0}A}{d}$

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Topic : capacitors

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