Question

the resultant magnitude of 6N force acting at right angle to 8N force is:

Answer 1

Answer:

Pythagoras Theoram,

Resultant = under root(36+64)

Resultant = 10N

Answer 2

Answer:

The Resultant of vectors perpendicular to each other can be solved in two ways:

Method one: Pythagoras Theorem

a2 + b2 = c2

In the case of vectors c is replaced by the resultant R

a2 + b2 = R2

6^2 + 8^2 = R2

36 + 64 = R2

100 = R2

R = 10N

Method two: cosine rule

R2 = a2 + b2 + 2*a*b*cosα

Where R is resultant and α represents the angle between vectors a and b.

R2 = 6^2 + 8^2 + 2*6*8*cos90

R2 = 36 + 64 + 0

R2 = 100

Take the square root of both sides

R = 10N

Hope it helps