The resultant molarity of solution made by mixing 600 mL of 2 M NaOH solution and 400 mL of 3M NaOH solution is
(1) 1 M
(2) 1.2 M
(3)2.4 M
(4) 3.6 M
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Answer:
(3) 2.4M
Explanation:
the rule is M1V1+M2V2=MV
where M1=2;M2=3;M= the resulting molarity
V1=600ml;V2=400ml;V=total volume
according to this
(2×600)+(3×400)=M×(600+400)
by solving we get 2.4
so the resultant molarity will be 2.4
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