the resultant of 2 forces one double the other in magnitude is perpendicular to smaller of 2 forces. the angle between 2 forces is?
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Let the forces be F and 2F respectively.
Let R be the resultant.
Given that R is perpendicular to F.
Therefore,
R^2 + F^2 = 4F^2
=>R^2 = 3F^2
R^2 = F^2 + 4F^2 + 2(F)(2F)Cosθ
3F^2 = 5F^2 + 4F^2Cosθ
-2F^2 = 4F^2Cosθ
Cosθ = - (1/2)
θ = Cos^-1(1/2) = 2π/3 = 120°
i hope it will help you
regards
Let R be the resultant.
Given that R is perpendicular to F.
Therefore,
R^2 + F^2 = 4F^2
=>R^2 = 3F^2
R^2 = F^2 + 4F^2 + 2(F)(2F)Cosθ
3F^2 = 5F^2 + 4F^2Cosθ
-2F^2 = 4F^2Cosθ
Cosθ = - (1/2)
θ = Cos^-1(1/2) = 2π/3 = 120°
i hope it will help you
regards
akshay122:
Can you plz expalin it on the page. Iam having problems in understanding this
Cos^-(1/2) means is cos inverse (1/2) and if u see ^ sign it means it in that power ...R^2 means R square...now i think u will understand
if you write with pen on page and solve the whole process and then send me i think it will be hepful
can u ask this question again i will their i will post a pic of this answer
ohk
i have done
send me link plzzz
i dont know how to send link
it's ohk i will
thnks
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