the resultant of the two forces p and q is r. if q is doubled the new resultant is perpendicular to p then
a. p=q
b. q=r
3. q= 2r
4. none of these
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Answer:
Option B ; i.e Q=R
Explanation:
Consider that Θ is the angle between P and Q having R resultant
Then we can say that;
R^2=P^2+Q^2+2PQcosΘ......a
When Q is doubled then let the resultant vector be R’
R’^2 = P^2+4Q^2+4PQcosΘ......b
As given in question statement, R’ is perpendicular to P
4Q^2=P^2+R’^2......c
Merging b and c
R’^2=P^2+P^2+R’^2+4PQcosΘ
2PQcosΘ = −P^2......d
Merging a and d we get
R^2=P^2+Q^2−P^2
Hence R=Q
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