Question

The resultant of two equal force each of 100n is 150n find the anglr between the direction of the two forces

Answer 1

Answer:

45°

Explanation:

Given,

A = 100 N

B = 150 N

Angle between A & B, θ = 45°

Resultant Force, |C| = √[|A|^2 +|B|^2 + 2|A||B|cosθ]

=> |C| = 231.73 N at an angle of ϕ = 27.23° from the direction of 100 N force.

• tan ϕ = b sinθ/(a + b cosθ)

______________________________

Resultant of a force is given by the formula R^2=(F1)^2+(F2)^2+2(F1)(F2)cosA

Where R is the resultant force

F1 is the force 1 = 100N

F2 is the force 2 = 150N

A is the angle between the two forces = 45°