Physics, asked by shobhanamaskeSakshi, 1 year ago

The resultant of two equal forces is 141.4N when they are mutually perpendicular. When they are inclined at an angle 120 degree then the resultant force will be?


shobhanamaskeSakshi: Please somebody try and tell me the answer

Answers

Answered by harshmata3oybvei
147
Hope this helps you...

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Answered by nirman95
0

Given:

  • Resultant of two equal perpendicular forces is 141.4 N

To find:

Resultant when the forces are 120° to one another?

Calculation:

Let the force be f :

Now, at 90° orientation, resultant is :

 \sqrt{ {f}^{2}  +  {f}^{2}  + 2.f.f \cos( {90}^{ \circ} ) }  = 141.4

 \implies \sqrt{ {f}^{2}  +  {f}^{2}   }  = 141.4

 \implies \sqrt{2 {f}^{2}    }  = 141.4

 \implies f \sqrt{2}  = 141.4

 \implies f = 100 \: N

Now, at 120° to one another, resultant will be:

r =  \sqrt{ {f}^{2}  +  {f}^{2} + 2.f.f. \cos( {120}^{ \circ} )  }

 \implies r =  \sqrt{ {f}^{2}  +  {f}^{2} +  2{f}^{2} ( - 0.5) }

 \implies r =  \sqrt{ {f}^{2}  +  {f}^{2}  - {f}^{2}  }

 \implies r =  \sqrt{ {f}^{2}  }

 \implies r = f

 \implies r = 100 \: N

So, resultant is 100 N

#SPJ3

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