Question

The resultant of two forces 3N and 4Nacting at right angle to each other.​

Answer 1

Answer:

By triangle method of vector addition :

$|A + B| = \sqrt{ {A}^{2} + {B}^{2} + 2AB \cos \theta } \\A = 3,B = 4 \: and \cos \theta = \cos 90 \degree \\ |A + B| = \sqrt{ {3}^{2} + {4}^{2} + 0 } \\ |A + B| = \sqrt{9 + 16} \\ |A + B| = \sqrt{25} \\ |A + B| =5$

5N is the resultant of two forces 3N and 4N acting at right angle to each other.

Answer 2

Answer:

5N

Explanation:

here u can use pythagoras theorem which is

3^2+4^2=5^2

so the resultant is 5N

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