The resultant of two forces each of magnitude F acting at a point is root F. What is the angle between the vectors ?
Answers
Answered by
18
Hey.
Here is the answer.
According to the question ,
√F is the resultant force.
Let the angle be x°
As, resultant force = √( F^2 + F^2 +2 F^2 cos x )
√F = √( F^2 + F^2 +2 F^2 cos x )
or, F = F^2 + F^2 +2 F^2 cos x
or, F = 2 F^2 + 2F^2 cos x
or, F = 2F^2(1+ cos x)
or, 1 = 2F ( 1+ cos x)
or, 1/2F = 1+ cos x
or, 0.5 F = 1 + cos x
or , 0.5 F - 1 = cos x
or, x = cos ^-1 (0.5F - 1)
Thanks.
Here is the answer.
According to the question ,
√F is the resultant force.
Let the angle be x°
As, resultant force = √( F^2 + F^2 +2 F^2 cos x )
√F = √( F^2 + F^2 +2 F^2 cos x )
or, F = F^2 + F^2 +2 F^2 cos x
or, F = 2 F^2 + 2F^2 cos x
or, F = 2F^2(1+ cos x)
or, 1 = 2F ( 1+ cos x)
or, 1/2F = 1+ cos x
or, 0.5 F = 1 + cos x
or , 0.5 F - 1 = cos x
or, x = cos ^-1 (0.5F - 1)
Thanks.
Answered by
1
let the angle between them be y
resultant force = √( F^2 + F^2 +2 F^2 cos y )
√F = √( F^2 + F^2 +2 F^2 cos y )
F = F^2 + F^2 +2 F^2 cos y
F = 2 F^2 + 2F^2 cos y
F = 2F^2(1+ cos y)
1 = 2F ( 1+ cos y)
1/2F = 1+ cos y
1/2 F = 1 + cos y
1/2 F - 1 = cos y
y = cos ^-1 (1/2F - 1)
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