Question

The resultant of two forces is 8KN and its direction is inclined at 60° to one of the forces whose
magnitude is 4KN. Find magnitude and direction of other force.​

Answer 1

Answer:

The way I view this problem is the resultant R is making a 60 degree angle from one of the forces, The two forces are at right angle from each other and they are the x-component Rx and the y- component Ry of the resultant. If the magnitude of Rx = 4N then the angle opposite the side is 30 degrees. The Ry component can be solved using the Pythagorean theorem.

R^2 = Rx^2 + Ry^2

8^2 = 4^2 + Ry^2

64 = 16 + Ry^2

Ry^2 = 64 - 16

Ry^2 = 48

Ry = 6.9282 N

Solving for the direction of Ry

Ry is 90 degrees from Rx

Explanation: