The resultant of two forces is 8KN and its direction is inclined at 60° to one of the forces whose
magnitude is 4KN. Find magnitude and direction of other force.
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The way I view this problem is the resultant R is making a 60 degree angle from one of the forces, The two forces are at right angle from each other and they are the x-component Rx and the y- component Ry of the resultant. If the magnitude of Rx = 4N then the angle opposite the side is 30 degrees. The Ry component can be solved using the Pythagorean theorem.
R^2 = Rx^2 + Ry^2
8^2 = 4^2 + Ry^2
64 = 16 + Ry^2
Ry^2 = 64 - 16
Ry^2 = 48
Ry = 6.9282 N
Solving for the direction of Ry
Ry is 90 degrees from Rx
Explanation:
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