The resultant of two forces of 12N and 16N is 20N. Find the angle between them.
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Solve using vector adddition
20^2 = 12^2 + 16^2 + 2x12x16cosθ
400 = 144 + 256 + 384cosθ
384cosθ = 0
Therefore θ=90 degrees
20^2 = 12^2 + 16^2 + 2x12x16cosθ
400 = 144 + 256 + 384cosθ
384cosθ = 0
Therefore θ=90 degrees
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