the resultant of two forces one is double im mag than other , is perpendicular to the smaller one .the angle between them will be
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Answer:
2\3pi
120'
We know
tan@=Q sin0/p+Q cos 0 ( read 0 as thetha)
@=90' , tan 90= undefined or 1/0
Therfore P+Qcos0= zero (0)
2P=Q [ given that Q=2P]
P+2P cos 0= zero (0)
Cos0 =-P/2P
Cos0=-1/2
0 (thetha)=120' or 2/3 pi
Hope This Helps :)
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