Question

the resultant of two forces P & Q acting at angle is

Answer 1

Answer:

taken in opposite orader based in triangle law......

Step-by-step explanation:

also the resultant is same effect or sum of another two vectors

....

like and

follow

Answer 2

Answer:

Step-by-step explanation:

In the first situation , (2m+1)  

2

(P  

2

+Q  

2

)

=P  

2

+Q  

2

+2PQcosα ....(1)

In the second situation, (2m−1)  

2

(P  

2

+Q  

2

)

=P  

2

+Q  

2

+2PQcos(90  

0

−α) ..........(2)

From (1), (P  

2

+Q  

2

)(4m  

2

+4m)

=2PQcosα and from (2)

(P  

2

+Q  

2

)(4m  

2

−4m)=2PQsinα

Dividing we get tanα=  

m+1

m−1

​