the resultant of two forces P & Q acting at angle is
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Answered by
0
Answer:
taken in opposite orader based in triangle law......
Step-by-step explanation:
also the resultant is same effect or sum of another two vectors
....
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Answered by
0
Answer:
Step-by-step explanation:
In the first situation , (2m+1)
2
(P
2
+Q
2
)
=P
2
+Q
2
+2PQcosα ....(1)
In the second situation, (2m−1)
2
(P
2
+Q
2
)
=P
2
+Q
2
+2PQcos(90
0
−α) ..........(2)
From (1), (P
2
+Q
2
)(4m
2
+4m)
=2PQcosα and from (2)
(P
2
+Q
2
)(4m
2
−4m)=2PQsinα
Dividing we get tanα=
m+1
m−1
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