The resultant of two forces P and Q is magnitude of P. If P is doubled then the resultant will be inclined to Q at which angle?
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Answer:
Heya user................❤
As we know,
R = P = [ P^2 + Q^2 + 2PQ cos theta ] ^1/2
Q ^2 + 2PQ cos theta =0
Hence,
Q + 2P cos theta =0..........(1)
Let the angle between resultant of 2P & Q be x
Therefore,
tan x = 2Psin theta / ( Q+2 P cos theta)
At last, from eq 1
tan x = Infinity -----> x
= 90°
Hope it’s helpful........ ☆(❁‿❁)☆
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